cudaMemcpyToSymbol issues

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When using cudaMemcpyToSymbol, you can directly use the name of the variable you are transferring data to. In fact, this is the only way it seems to work. var, &var, etc. all do not have the desired effect, despite the function seeming to request a const char or a pointer. Also note that if you are including the cudaMemcpyKind, then it is the fifth parameter, not the fourth. The fourth parameter is an offset.