cudaMemcpyToSymbol issues

When using cudaMemcpyToSymbol, you can directly use the name of the variable you are transferring data to. In fact, this is the only way it seems to work. var, &var, etc. all do not have the desired effect, despite the function seeming to request a const char or a pointer. Also note that if you are including the cudaMemcpyKind, then it is the fifth parameter, not the fourth. The fourth parameter is an offset.